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6x^2-64x+104=0
a = 6; b = -64; c = +104;
Δ = b2-4ac
Δ = -642-4·6·104
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-40}{2*6}=\frac{24}{12} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+40}{2*6}=\frac{104}{12} =8+2/3 $
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